A particle is projected from a point A with a velocity v at an angle θ θ (upward) to the horizontal. At a certain point B, it moves at right angle to its initial direction. It follows that
A
Velocity of the particle at B is v
B
Velocity of the particle at B is v cot θ θ .
C
Velocity of the particle at B is v tan θ θ .
D
The time of flight from A to B is 
.
.
Text Solution
Verified by ExpertsThe correct answer is:
D
considering along the line AC
0 = v – g sin θ θ t
⇒ ⇒ t = 
Now consider along the line CB
v ′ ′ = 0 + g cos θ θ 
,
Hence, is correct
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